Question

I have next model:

class People(models.Model):
    name = models.CharField(max_length=100)
    lastname = models.CharField(max_length=100)

class Salary(models.Model):
    id_of_people=models.ForeignKey(People)
    salary = models.IntegerField(required=False)

In views.py

-When I try this one:

    for each in People.objects.all()[:3]:
            Salary().id_of_people_id=each.id
            Salary().save()

It only saves 3 Th id, not from 1 to 3. So, it only saves one time. But, I want to loop through all 3 records, why this happens ? How to add all People table id’s to Salary table ?

Answer 1

You’re creating a single Salary object and updating it three times. You need to create three separate objects.

for each in People.objects.all()[:3]:
    item_salary=Salary()
    item_salary.id_of_people_id=each.id
    item_salary.save()