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Home/ Questions/Q 4567124
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Editorial Team
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Editorial Team
Asked: May 21, 20262026-05-21T18:53:10+00:00 2026-05-21T18:53:10+00:00

I have next problem: x=[[‘1’, ‘7’, ‘U1’], [‘1.5’, ‘8’, ‘U1’]] y=sum(sum(float(el) for el in

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I have next problem:

x=[['1', '7', 'U1'], ['1.5', '8', 'U1']]
y=sum(sum(float(el) for el in els[:-1]) for els in x) 

print(x)
print(y)

In this code sum, sum all numbers, but I want to sum from first [‘1’, ‘7’, ‘U1’], first number, and from second [‘1.5’, ‘8’, ‘U1’] first number, and same for second…

so final result fill look as “matrix” :

y=
[ [2.5],                                #1+1.5=2.5
  [15]]                                 #7+8=15
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  1. Editorial Team
    Editorial Team
    2026-05-21T18:53:10+00:00Added an answer on May 21, 2026 at 6:53 pm
    >>> x=[['1', '7', 'U1'], ['1.5', '8', 'U1']]
    >>> zip(*x)
    [('1', '1.5'), ('7', '8'), ('U1', 'U1')]
    >>> [[sum(float(n) for n in nums)] for nums in zip(*x)[:-1]]
    [[2.5], [15.0]]
    

    zip(*x) is a simple way to transpose the matrix (switch rows <–> columns), and this allows you to easily sum each row.

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