Question

I have next sql

select site_id,count from tags where match (tag) against ('statistici' in boolean mode) ORDER BY count DESC;

+---------+-------+
| site_id | count |
+---------+-------+
|       9 |  1300 |
|      13 |  1200 |
|       9 |  1100 |
|      13 |  1000 |
|       9 |   900 |
|      13 |   800 |
|      13 |   800 |
+---------+-------+

What i need is to get distinct site_id.
But when i use a group by statement the order by count is not kept

select site_id,count from tags where match (tag) against ('statistici' in boolean mode) GROUP by site_id ORDER BY count DESC;

+---------+-------+
| site_id | count |
+---------+-------+
|      13 |  1000 |
|       9 |   900 |
+---------+-------+

What should i do ?

Answer 1

You’re ordering by ORDER BY count DESC, and the result is ordered with the highest count first.

Change to ORDER BY count ACS if you prefer the lowest count first.

EDIT: Based on your comment, perhaps this is more like what you’re trying to achieve:

select  site_id
,       max(count) as TopCount
from    tags 
where   match (tag) against ('statistici' in boolean mode) 
group by 
        site_id 
order by
        TopCount DESC

This selects the highest count per site, and places the highest count first.