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Home/ Questions/Q 8492465
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Editorial Team
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Editorial Team
Asked: June 10, 20262026-06-10T22:43:39+00:00 2026-06-10T22:43:39+00:00

I have no idea if I can just run this code and it will

  • 0

I have no idea if I can just run this code and it will work but here:

public void actionPerformed(ActionEvent e) {
        try
        {
        Runtime rt = Runtime.getRuntime();
        Process p = rt.exec("c:\\Users\\Toby\\AppData\\Roaming\\.minecraft\\minecraft.exe");
        }

        catch(Exception a)
        {

        }
    }

This is linked to a button, and it launches the minecraft launcher. If I want to give it to my friends, what do I have to do so that it doesn’t look for the user ‘Toby’, but instead looks for their home folder? Sorry if its confusing!

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  1. Editorial Team
    Editorial Team
    2026-06-10T22:43:41+00:00Added an answer on June 10, 2026 at 10:43 pm

    I think you’re looking for the user.home property. There’s a list of properties available here: http://www.mindspring.com/~mgrand/java-system-properties.htm

    So, your code would be changed to:

    Process p = rt.exec(System.getProperty("user.home") + \\AppData\\Roaming\\.minecraft\\minecraft.exe");
    
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