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Home/ Questions/Q 540107
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Editorial Team
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Editorial Team
Asked: May 13, 20262026-05-13T10:12:21+00:00 2026-05-13T10:12:21+00:00

I have no problem converting normal double values, but I can’t convert numeric_limits<double>::max( )

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I have no problem converting “normal” double values, but I can’t convert numeric_limits<double>::max() or DBL_MAX string representations?

std::string max = "1.79769313486232e+308";

std::istringstream stream(max);
double value;

// enters here, failbit is set
if (!(stream >> value))
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  1. Editorial Team
    Editorial Team
    2026-05-13T10:12:21+00:00Added an answer on May 13, 2026 at 10:12 am

    Could it be something like the actual value of DBL_MAX isn’t exactly representable in exponential notation with 16 decimal places (say the decimal value is very slightly larger than the two based represenation) but initializing a double with the DBL_MAX will nevertheless set the correct value (due to rounding). std::istringstream may be a little bit more pickish.

    EDIT: Actually I found that the value of DBL_MAX in my compiler is 1.7976931348623158e+308 which works fine for me to stream. Your number is rounded and slightly larger, hence the failure.

    EDIT2: The exact value of DBL_MAX in decimal form is given by (2 ^ (1023 - 52)) * (2 ^ 53 - 1) which isn’t representable with 16 decimal places.

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