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Home/ Questions/Q 7982097
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T10:34:32+00:00 2026-06-04T10:34:32+00:00

I have NSMutableArray* names , which contains NSStrings. I want to sort the array

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I have NSMutableArray* names, which contains NSStrings. I want to sort the array with the caseInsensitiveCompare method.

This is the code I’ve written:

names= [names sortedArrayUsingComparator: ^ NSComparisonResult (id obj1, id obj2)
            {
                return [obj1 caseInsensitiveCompare: obj2];
            }];

The problem is that sortedArrayUsingComparator returns a NSArray instead of a NSMutableArray, and I get a warning and problems at runtime with this code.
Is there is a way to cast the NSArray to a NSMutableArray? Or do I have to copy all of the elements? This last solution is expensive: could someone suggest a nice, low overhead solution?

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  1. Editorial Team
    Editorial Team
    2026-06-04T10:34:33+00:00Added an answer on June 4, 2026 at 10:34 am

    Note that the name of the function that you are using (sortedArrayUsingComparator) tells you that it is going to return an array and not a mutable array. Use the mutableCopy method of NSArray to get a mutable copy.

    names= [[names sortedArrayUsingComparator: ^ NSComparisonResult (id obj1, id obj2)
           {
               return [obj1 caseInsensitiveCompare: obj2];
           } ] mutableCopy];
    

    Or, easier to read / follow:

    NSArray *namesArray = [names sortedArrayUsingComparator:^NSComparisonResult (id obj1, id obj2) {
           return [obj1 caseInsensitiveCompare: obj2];
           }];
    names = [namesArray mutableCopy];
    
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