Question

I have on HTML file in which I have inserted the custom tags like {{name}}, {{surname}}. Now I want to search the tags who exactly match the pattern like {{world}} only not even {world}}, {{world}, {world}, { word }, {{ world }}, etc.
I wrote the small code for the

re.findall(r'\{(\w.+?)\}', html_string)

It returns the words which follow the pattern {{world}} ,{world},{world}}
that I don’t want. I want to match exactly the {{world}}. Can anybody please guide me?

Answer 1

Um, shouldn’t the regex be:

'\{\{(\w.+?)\}\}'

Ok, after the comments, I understand your requirements more:

'\{\{\w+?\}\}'

should work for you.

Basically, you want {{any nnumber of word characters including underscore}}. You don’t even need the lazy match in this case actually so you may remove th ? in the expression.

Something like {{keyword1}} other stuff {{keyword2}} will not match as a whole now.

To get only the keyword without getting the {{}} use below:

'(?<=\{\{)\w+?(?=\}\})'