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Home/ Questions/Q 7025801
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T00:01:41+00:00 2026-05-28T00:01:41+00:00

I have on page div: <div id=here_table></div> and in jquery: for(i=0;i<3;i++){ $(‘#here_table’).append( ‘result’ +

  • 0

I have on page div:

<div id="here_table"></div>

and in jquery:

for(i=0;i<3;i++){
    $('#here_table').append( 'result' +  i );
}

this generating for me:

<div id="here_table">
    result1 result2 result3 etc
</div>

I would like receive this in table:

<div id="here_table">
    <table>
          <tr><td>result1</td></tr>
          <tr><td>result2</td></tr>
          <tr><td>result3</td></tr>
    </table>
</div>

I doing:

$('#here_table').append(  '<table>' );

 for(i=0;i<3;i++){
    $('#here_table').append( '<tr><td>' + 'result' +  i + '</td></tr>' );
}

 $('#here_table').append(  '</table>' );

but this generate for me:

<div id="here_table">
    <table> </table> !!!!!!!!!!
          <tr><td>result1</td></tr>
          <tr><td>result2</td></tr>
          <tr><td>result3</td></tr>
</div>

Why? how can i make this correctly?

LIVE: http://jsfiddle.net/n7cyE/

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-28T00:01:42+00:00Added an answer on May 28, 2026 at 12:01 am

    This line:

    $('#here_table').append( '<tr><td>' + 'result' +  i + '</td></tr>' );
    

    Appends to the div#here_table not the new table.

    There are several approaches:

    /* Note that the whole content variable is just a string */
    var content = "<table>"
    for(i=0; i<3; i++){
        content += '<tr><td>' + 'result ' +  i + '</td></tr>';
    }
    content += "</table>"
    
    $('#here_table').append(content);
    

    But, with the above approach it is less manageable to add styles and do stuff dynamically with <table>.

    But how about this one, it does what you expect nearly great:

    var table = $('<table>').addClass('foo');
    for(i=0; i<3; i++){
        var row = $('<tr>').addClass('bar').text('result ' + i);
        table.append(row);
    }
    
    $('#here_table').append(table);
    

    Hope this would help.

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