Question

I have one-dimensional-array $abc.

$abc = array (90, 91, 92, 93, 94, 95, 96, 97, 98, 99);

I want to use it in WHERE IN

SELECT *
FROM table
WHERE columnA IN ()

while (){
$def[] = $row['def'];  
} 

When I use simple IN(‘$abc’) I have a response – Undefined variable: def

How to do it properly?

Answer 1

You can use implode() function:

$abc = array (90, 91, 92, 93, 94, 95, 96, 97, 98, 99);
$str = implode(',', $abc);

Now you can use $str in IN clause.

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Learn more about implode() function.