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Asked: 2026-05-27T09:37:48+00:00

I have one HTML file located in app/views/layouts/application.html.erb I use <%=yield=> to render the

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I have one HTML file located in app/views/layouts/application.html.erb

I use <%=yield=> to render the HTML code from other models.
The problem is that I don’t know how to distinguish the CSS code. I have a universal CSS code, but each html file needs a different one.

here is my CSS line in app/views/layouts/application.html.erb

<%= stylesheet_link_tag "scaffold" %>
<%= stylesheet_link_tag "welcome_screen/my_CSS.css", :media => "all" %>
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1 Answer

  1. Editorial Team

    put a named yield in the head of the layout file, then use content_for in your specific view

    # application.html.erb
<head>
    <%= stylesheet_link_tag "scaffold" %>
    <%= yield(:head) %>
    # ...
</head>
<body>
    <%= yield %>
    # ...
</body>

    then your view code

    # welcome_screen.html.erb
<% content_for(:head) do %>
    <%= stylesheet_link_tag "welcome_screen/my_CSS.css", :media => "all" %>  
<% end %>
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