Question

i have one interface like,

public interface Details
{
    int Id { get; set; }
    string Name { get; set; } 
}        

And i have one method in another class like

public void GetDetails()      
{ 
    List<Details> lstDetails = new List<Details>();        
    DetailsImpl objDetailsImpl;
    Details objDetails = new DetailsImpl();
    for (int i = 1; i <= 2; i++)
    {
        objDetailsImpl = new DetailsImpl(); //The **DetailsImpl** class is given below
        objDetails.Id = i;
        if(i==1)
           objDetails.Name = "FirstName";
        else
           objDetails.Name = "SecondName";
        lstDetails.Add(objDetails);
    }
    objDetailsImpl.InsertRecords(lstDetails);  
}

And i write InsertRecords methods in another derived class like,

public class DetailsImpl : Details
{
    Dictionary<object, object> objDictionary = new Dictionary<object, object>();
    public string Name { get; set; }
    public int Id { get; set; }

    public int InsertRecords(List<Details> lstDetails)
    {
        for (int i = 0; i < lstDetails.Count; i++)
        {
            //i want to get the integer value "Id" from List(lstDetails)
            Id = //How to get the Id value based on count, now the <lstDetails> count is 2

            //i want to get the Name object value also, how to i get???
            Name = Convert.ToString(String.Join(",",lstDetails.Select(s => s.Name).ToArray()));
            //If i using the above line for getting **Name** value means, its comes like "FirstName,LastName", but i want **Name** value based on row.....


            objDictionary.Clear();
            objDictionary.Add("@Id",Id);
            objDictionary.Add("@Id",Name);
            //Here i passed this parameter to "ExecuteNonQry" method for insert operations
            ExecuteNonQry("sp_name",objDictonary,CommandType.StoredProcedure);
        }
        return 1;
    }
}

I want to get Id, Name object values based on list count. How to i solve this?

Answer 1

The Name property of the ith element is

lstDetails[i].Name

It’s worth pointing out that you do not have a List<> you have a List<T> – and you’re not telling us what the T is.