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Home/ Questions/Q 7645341
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Editorial Team
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Editorial Team
Asked: May 31, 20262026-05-31T09:55:01+00:00 2026-05-31T09:55:01+00:00

I have one line of code that is throwing an error that I don’t

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I have one line of code that is throwing an error that I don’t care about. I need to hide it from the console. I don’t want to use a custom error handler and return false, because I want to see all other errors.

I’ve tried a try / catch, but the error still shows up in the console:

try{
    //the erroneous line of code
}catch(err){ }

I’ve also tried fiddling window.onerror right before the erroneous line, and fiddling it back right after, and the error still shows up in this case as well:

window.onerror = function(){ return false; }
//erroneous line of code
window.onerror = function(){ return true; }

Any help would be appreciated.

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-31T09:55:03+00:00Added an answer on May 31, 2026 at 9:55 am

    try catch is the one to use

    b=a; // gives an error in the console
    try {
      a = x; // does NOT give an error in the console
    }
    catch(e) {
      document.getElementById('error').innerHTML='ERROR: '+e.message;
    }  
    

    I only get

    a is not defined

    in the console in my fiddle

    I do not get the SECOND error in the console. Not even after commenting out the first error just in case it possibly blocked further processing.

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