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Home/ Questions/Q 6641959
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Editorial Team
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Editorial Team
Asked: May 25, 20262026-05-25T23:52:24+00:00 2026-05-25T23:52:24+00:00

I have one ListView, it contains check boxes. By default all check boxes are

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I have one ListView, it contains check boxes. By default all check boxes are checked, if we uncheck any check box the position will be added to mCheckedArrayList. Now I want remove all unchecked positions from the Listview. I used the following code:

for(int i=0;i<=mCheckedArrayList.size;i++){
    int removePosition=mCheckedArrayList.get(i);
    mDisplayArrayList.remove(removePosition);
}

But it is giving an ArrayIndexOutOfBounds exception.

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  1. Editorial Team
    Editorial Team
    2026-05-25T23:52:25+00:00Added an answer on May 25, 2026 at 11:52 pm

    You are removing objects in the wrong order. You should always reverse the order of the loop if you are removing elements within the loop:

    for(int i = mCheckedArrayList.size()-1 ; i >= 0; i--){
        mDisplayArrayList.remove(mCheckedArrayList.get(i));
    }
    

    As a side note, if you wanted to loop through front first (in cases where you are not deleting elements), you would have to change your loop end condition to the following:

    i < mCheckedArrayList.size()
    

    Thanks to Martín for the comment. To be aware of modifications you could always use a ‘final ref’ of the array.

    final ArrayList<T> arrayListToBeUsed = mCheckedArrayList;
    for(int i = arrayListToBeUsed .size()-1 ; i >= 0; i--){
        arrayListToBeUsed .remove(arrayListToBeUsed .get(i));
    }
    
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