Question

I have one template function which will take a pointer type and i have instantiated it before calling.
i have written function with its dummy implementation as follows:

template<T>fun_name( const T *p )
{
  //written functionality which will give me class name that i will store into string Variable
  e.g. i got output like this string Var = "First_class" or string Var = "Second_class"   

  //Using this class name i will call one function of that class
    if(Var == "Fisrt_class") 
    {   
    First_class::static_function_name(p);
    }
    if(Var == "Second_class")
    { 
    Second_class::static_function_name(p);
    }

}

and in global scope i instantiated this function for two variables as like below:

template<first_class>static_function_name(const First_class *)
template<Second_class>static_function_name(const Second_class *)

above code gives me error that

error: no matching function call in Second_class::static_function_class(const Fisrt_class*)
error: no matching function call in First_class::static_function_class(const Second_class*)

thanks in advance!

Answer 1

I think this :

template<typename T> // template<class T> is equally valid!
void fun_name( const T *p )
{
  T::static_function_name(p);
}

is enough!

Two more errors is fixed in the above code:

• Mention the keyword typename in template<T> in your code. You can also write template<class T> which is equally valid.
• Mention the return type of the function template as well.