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Home/ Questions/Q 783337
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Editorial Team
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Editorial Team
Asked: May 14, 20262026-05-14T20:31:52+00:00 2026-05-14T20:31:52+00:00

I have Page A which calls Page B using AJAX. Page B will be

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I have Page A which calls Page B using AJAX. Page B will be put in a div container in Page A. Within the result (which is Page B), there’s a code that will initiate a jQuery UI Dialog. The div for the dialog is also in Page B. However, it doesn’t work. I’d have to put the initiation code in Page A. So, if I want to put the initiation code in Page B, what should I do ?

The initiation code:


$('#dialog').dialog({
    bgiframe: true,
    autoOpen: false,
    width: 300,
    height: 300,
    modal: true,
    resizable: false,        
    buttons: {
        'Create an account': function() { },
         Cancel: function() { }
    },
    close: function() { }
});

I've also tried using $('div.dialog') as the selector (changed the id to class) and it does work, but everytime I request Page B (without reloading Page A), the dialog will multiply. For an example, the first time I requested Page B, one dialog will be opened. The second time I requested Page B, two dialogs will be opened.

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  1. Editorial Team
    Editorial Team
    2026-05-14T20:31:52+00:00Added an answer on May 14, 2026 at 8:31 pm

    Your approach isn’t far off, you’re just duplicating the dialog on the call when loading each time, so destroy the previous one, so instead of this:

    $('div.dialog').dialog({ ...options... });
    

    Call this:

    $('div.dialog').dialog('destroy').dialog({ ...options... });
    

    This prevents multiple dialogs from being instantiated for the same element. Alternatively, you can check if the dialog has been created on that element yet, like this:

    $('div.dialog').filter(function() {
      return $(this).closest('.ui-dialog').length === 0;
    }).dialog({ ...options... });
    

    This creates the dialog only on <div class="dialog"> elements that aren’t already wrapped in a dialog.

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