Question

I have possible inputs 1M 2M .. 11M and 1Y (M and Y stand for months ) and I want to output “somestring1 somestring2…. and somestring12” note M and Y are removed and the last string is changed to 12

    Example: input "11M" "hello" output: hello11
             input "1Y" "hello" output: hello1



char * (const char * date, const char * somestr)
{
    // just need to output final string no need to change the original string
    cout<< finalStr<<endl;
}

Answer 1

is this homework? If not, here’s what i’d suggest. (i ask about homework because you may have restrictions, not because we’re not here to help)

1) do a find on ‘M’ in your string (using find), insert a ‘\0’ at that position if one is found (btw i’m assuming you have well formatted input)

2) do a find on ‘Y’. if one is found, insert a ‘\0’ at that position. then do an atoi() or stringstream conversion on your string to convert to number. multiply by 12.

3) concatenate your string representation of part 1 or part 2 to your somestr

4) output.

This can probably be done in < 10 lines if i could be bothered.
the a.find(‘M’) part and its checks can be conditional operator, then the conversion/concatenation in two or three lines at most.