Question

I have posted a sample jQuery slideshow on my blog here:
robertmarkbramprogrammer.blogspot.com/2010/09/jquery-slideshow.html

In Chrome, it is flickering on each picture. In IE and Firefox it looks fine, and in the standalone version it seems ok too (even on Chrome):
http://robertmarkbram.appspot.com/content/javascript/jQuery/example_slideshow.html

This is the jQuery in question:

<script type="text/javascript">
   // ------
   // ###### Edit these.
   // Assumes you have images in path named 1.jpg, 2.jpg etc.
   var imagePath = "images";  // Relative to this HTML file.
   var lastImage = 5;         // How many images do you have?
   var fadeTime = 4000;       // Time between image fadeouts.
 
   // ------
   // ###### Don't edit beyond this point.
   var index = 1;
   function slideShow() {
      $('#slideShowFront').show();
      $('#slideShowBack').show();
      $('#slideShowFront').fadeOut("slow")
            .attr("src", $("#slideShowBack").attr("src"));
      index = (index == lastImage) ? 1 : index + 1;
      $("#slideShowBack").attr("src", imagePath + "/" + index + ".jpg")
      setTimeout('slideShow()', fadeTime);
   }
 
   $(document).ready(function() {
      slideShow();
   });
</script>

Any assistance would be greatly appreciated!

Rob
🙂

Answer 1

There are 2 possible causes of the flicker.

The first is from the line $('#slideShowBack').show();.

Just remove that line, since it does nothing, since the visibility of #slideShowBack is never changed.

The second is when you .show() the front image over the back image. Even though the front image is now the same as the back image, it could be causing a momentary flicker.

I would approach the problem slightly differently.

1. Start the HTML page with just one image (this is semantically more meaningful, since the second image is not visible…. you could also start with all the images in the DOM, but that’s a different approach).
2. Call the slideshow function for the first time with image #2.
3. Slideshow – Add the new image to the DOM behind the current image
4. Slideshow – Fade the current image revealing the new image behind it.
5. Slideshow – Remove the just faded image from the DOM.
6. Slideshow – After a pause call the slideshow with the next image

I would also enclose all your variables and functions in a self calling anonymous function, so that you don’t clutter the global namespace: (function() { /* Everything in here */ })();.

The most important change in the code is that I don’t suddenly .show() an image on top of another image, so there’s no possible source of flicker. I also make use of the call back function in .fadeOut(). This is just a function that is called after the fade is done:

The HTML:

<div id="slideShow"> 
   <img src="images/1.jpg" /> 
</div>

The Javascript:

  // Contain all your functionality in a self calling anonymous
  //   function, so that you don't clutter the global namespase.
(function() {
    // ------
    // ###### Edit these.
    // Assumes you have images in path named 1.jpg, 2.jpg etc.
    var imagePath = "images";
    var lastImage = 5;         // How many images do you have?
    var fadeTime = 4000;       // Time between image fadeouts.

    // ------
    // ###### Don't edit beyond this point.
    // No need for outer index var
    function slideShow(index) {          
        var url = imagePath + "/" + index + ".jpg";
          // Add new image behind current image
        $("#slideShow").prepend($("<img/>").attr("src",url));
          // Fade the current image, then in the call back
          //   remove the image and call the next image
        $("#slideShow img:last").fadeOut("slow", function() {
            $(this).remove();
            setTimeout(function() { 
                slideShow((index % lastImage) + 1) 
            }, fadeTime);
        });
    }
    $(document).ready(function() {
          // Img 1 is already showing, so we call 2
        setTimeout(function() { slideShow(2) }, fadeTime);
    });
})();  

jsFiddle ​

Calling the next slideshow function:
Instead of index = (index == lastImage) ? 1 : index + 1; you can use the modulus operator % to get the remainder from a division, and instead of using a looping variable you have to set outside the slideShow() function, just pass which photo you want to show in as an argument… Then you can call the next showImage in your setTimeout with slideShow(current+1). Actually, slideShow((index % lastImage) + 1). It’s better to use an anonymous function or a reference with setTimeout instead of an eval.