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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T21:19:18+00:00 2026-06-04T21:19:18+00:00

I have probably missed something important on QString argument manipulation. Can’t find the reason

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I have probably missed something important on QString argument manipulation.

Can’t find the reason why just str2 gives valid result. I’ve found few examples which are written in manner str1 so I guess it should work. Thanks.

QString str1 = QString("%1");
str1.arg("help");
qDebug() << QString("str1 - ") + str1;

QString str2 = QString("%1").arg("help");
qDebug() << QString("str2 - ") + str2;

Results in:

"str1 - %1" 
"str2 - help" 
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  1. Editorial Team
    Editorial Team
    2026-06-04T21:19:20+00:00Added an answer on June 4, 2026 at 9:19 pm

    try to assign the value of arg()

    so use the returned value instead

    e.g.

    QString str1 = QString("%1");
    str1 =str1.arg("help");
    qDebug() << QString("str1 - ") + str1;
    
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