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Editorial Team
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Asked: 2026-06-10T10:10:50+00:00

I have problem to only execute one of the script at a time when

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I have problem to only execute one of the script at a time when one of the button is click. The code execute 2 script together when the button is click. How can I only execute one script at a time and specific button execute specific script. Thanks for the help. Below is my code. 

<html>
<head>
<script language="javascript" type="text/javascript">
    function popup(){
        window.location = 'testing.php?run=shell';
    }
    function popdown(){
        window.location = 'testing.php?run=shell';
    }
</script>
</head>
<body>
<input type="button" onclick="popup()" value="popup">
<?php
if(isset($_GET['run']) && ($_GET['run'] == 'shell')){
    echo shell_exec('sh bash_test.sh');
}
?>
<input type="button" onclick="popdown()" value="popdown">
<?php
if(isset($_GET['run']) && ($_GET['run'] == 'shell')){
    echo shell_exec('sh bash_run.sh');
}
?>
</body>
</html>
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1 Answer

  1. Editorial Team

    Try this:

    <html>
<head>
<script language="javascript" type="text/javascript">
    function popup(){
        window.location = 'testing.php?run=test';
    }
    function popdown(){
        window.location = 'testing.php?run=run';
    }
</script>
</head>
<body>
<input type="button" onclick="popup()" value="popup">
<?php
if(isset($_GET['run']) && ($_GET['run'] == 'test')){
    echo shell_exec('sh bash_test.sh');
}
?>
<input type="button" onclick="popdown()" value="popdown">
<?php
if(isset($_GET['run']) && ($_GET['run'] == 'run')){
    echo shell_exec('sh bash_run.sh');
}
?>
</body>
</html>
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