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Home/ Questions/Q 7194019
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Editorial Team
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Editorial Team
Asked: May 28, 20262026-05-28T20:17:12+00:00 2026-05-28T20:17:12+00:00

I have problem understanding this one: <?php $string = ‘April 15, 2003’; $pattern =

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I have problem understanding this one:

<?php
$string = 'April 15, 2003';
$pattern = '/(\w+) (\d+), (\d+)/i';
$replacement = '${1}1,$3';
echo preg_replace($pattern, $replacement, $string);
?>

Output is April1,2003. I don’t understand this expression: $replacement = '${1}1,$3';
Would appreciate if somebody clarifies it for me.

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  1. Editorial Team
    Editorial Team
    2026-05-28T20:17:14+00:00Added an answer on May 28, 2026 at 8:17 pm

    Programmer had to use this, because

    $replacement = '$11,$3'; 
    

    would act weird and wrong. Also, they couldn’t use

    $replacement = '$1'.'1,$3'; 
    

    too,because it would cause it to be parsed as the first example.

    That’s why there are these brackets, they work as a delimiter between the variable and number 1.

    It’s the same as

    $username = "Martin"
    $text = "Hello ${username}and welcome";
    

    above example will output “Hello Martinand welcome”

    but this one

    $username = "Martin";
    $text = "Hello $usernameand welcome";
    

    is mistchmashing the variable name with plain text, which is in your replacement, number 1

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