Question

I have problem with ajax and php.I have next code

$("form").submit(function() {
 var poruka = $("#poruka").val();
  $.ajax({
        type: "GET",
        url: "/ajax/gather/send/"+ poruka + "/'.$id.'",
        success: function(){
         loaduj('.$id.');
         alert("Your message is "+poruka);
        },
        error: function(){
            alert("fail");
        }
    });
});

“poruka” is the message and it’s taken from form

<form action='javascript:;'>
<input type='text' name='poruka' id='poruka' placeholder='Poruka..' style='width:100%;'>
<input type='button' name='button' hidden>
</form>

And when i try to send to php it won’t insert that into database :

Php code :

$text = $_POST['text'];
$id = $_POST['id'];
if($text != ""){
  mysql_query("INSERT INTO messages (text,id2) VALUES ('$text','$id')") or     die(mysql_error());
}

And it can’t work..How can i fix it ? Thanks

Answer 1

You use POST instead of GET. In your AJAX form you specify that you use GET, but in PHP you use $_POST superglobal.

Change $_POST into $_GET in your PHP code and it should work 🙂

Also if you do not specify method in your tag, the default is GET.

From experience, in case if the data from the form is not written/updated in/to the database use

echo mysql_error();

after the MySQL query and also open the developer tools on your browser and inspect in the network panel. Developer tools can be opened using F12 and with CTRL+SHIFT+I if your F12 is not working due to the coffee spilled on it. Network panel shows the data being sent, the method used and every other detail of a network call. Also there you can see the response of your server side script which in this case would return a mysql error message because you echo’ed it out.