Question

I have problem with reg ex. in PHP
I have string like:

sdfsfds dsfdsh kj <img src="cid:sdfsdf/img.jpg@23232"> sdfd sfdhg sdjhg sdfsfds dsfdsh kj <img src="cid:sdfsdf/img.jpg@23232"> sdfd sfdhg sdjhg 

I want to grab everything between ‘cid:’ and ‘”>’ and replace it with something else.
Here is my reg ex:

cid:.*img\.jpg.*\"

What do I get in return??

cid:sdfsdf/img.jpg@23232"> sdfd sfdhg sdjhg sdfsfds dsfdsh kj <img src="cid:sdfsdf/img.jpg@23232"

insead of double

cid:sdfsdf/img.jpg@23232

why??

Answer 1

Your regex is greedy. Use non-greedy quantifiers by adding a ? after them:

cid:.*?img\.jpg.*?\"

http://en.wikipedia.org/wiki/Regular_expression#Lazy_quantification