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Home/ Questions/Q 907673
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Editorial Team
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Editorial Team
Asked: May 15, 20262026-05-15T16:35:29+00:00 2026-05-15T16:35:29+00:00

I have problems understanding why when I create two or more nodes (as shown

  • 0

I have problems understanding why when I create two or more nodes (as shown below), the function void del_end()will only delete the char name[20] and not the whole node . How do I fix this problem without memory leak?

#include <iostream>
using namespace std;

struct node
{
    char name[20];
    char profession[20];
    int age;
    node *nxt;
    node *prv;
};

node *start_ptr = NULL;

void del_end()
{
    node *temp, *temp2;
    temp = start_ptr;
    if (start_ptr == NULL)
        cout << "Can't delete: there are no nodes" << endl;
    else if (start_ptr != NULL && start_ptr->nxt == NULL)
    {start_ptr=NULL;}
    else
    {
    while (temp->nxt != NULL)
    {
        temp = temp->nxt;
    }
    temp2=temp->prv;
    delete temp;
    temp->nxt= NULL;
    }
}
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  1. Editorial Team
    Editorial Team
    2026-05-15T16:35:30+00:00Added an answer on May 15, 2026 at 4:35 pm

    Your code has some problems, the worst being here:

    temp2=temp->prv;
    delete temp2;
    temp->nxt= NULL;
    

    You’re deleting the next-to-last node, leaving any pointers to it dangling, and losing the last node.

    But if you post more of the real code, we can tell you more.

    EDIT:
    Here’s a slightly cleaned-up version of del_end (and there’s still plenty of room for improvement).

    void del_end()
    {
      if (start_ptr == NULL)
      {
        cout << "Can't delete: there are no nodes" << endl;
        return;
      }
    
      if (start_ptr->nxt == NULL)
      {
        delete start_ptr;
        start_ptr = NULL;
        return;
      }
    
      node *nextToLast = start_ptr;
      node *last = start_ptr->nxt;
    
      while(last->nxt != NULL)
      {
        nextToLast = last;
        last = last->nxt;
      }
    
      delete last;
      nextToLast->nxt = NULL;
    
      return;
    }
    

    Note that this does not assume that the prev links are correct, which seems prudent here.

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