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Home/ Questions/Q 1037765
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Editorial Team
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Editorial Team
Asked: May 16, 20262026-05-16T14:53:25+00:00 2026-05-16T14:53:25+00:00

I have problems with jquery accordion. It seems quite tricky. The first accordion, project1,

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I have problems with jquery accordion. It seems quite tricky.

The first accordion, project1, is working great (thanks to Nick Craver) but 2nd & 3rd an so on does not work. I do not really know if I should use .filter.

Here is the code & example page: http://jsfiddle.net/THjgV/2/

Thank you.

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  1. Editorial Team
    Editorial Team
    2026-05-16T14:53:26+00:00Added an answer on May 16, 2026 at 2:53 pm

    Since they all have different heights, you need to store and use each height independently, I suggest using $.data() and .data() for this. Also change your IDs to classes as they should be unique.

    $('.slickbox').hide().each(function() {
        $.data(this, 'height', $(this).height());
    });
    $('.more a').toggle(function() {
        var sb = $(this).parent().prev('.slickbox').slideDown(3200);
        $('html, body').animate({
            scrollTop: '+=' + sb.data('height')
        }, 3200);
        return false;
    }, function() {
        var sb = $(this).parent().prev('.slickbox').slideUp(3200);
        $('html, body').animate({
            scrollTop: '-=' + sb.data('height')
        }, 3200);
        return false;
    });
    

    You can test it out here, this loops through and stores the heights of each .slickbox (now using a class!) and stores it. When each link is clicked it’s specifically toggling the class="slickbox" element that precedes it, and uses it’s stored 'height' value for scrolling.

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