Question

I have program that asks to enter a string (mystring) and a char (ch). Then it deletes all entered chars (ch) from the string (mystring). For example “abcabc” and char ‘a’ then the result shoud be “bcbc”.
-When I use scanf the program works nicely if the string does not have spaces. If I enter “abc abc abc” It reads and processes only the first 3 letters (until space).
Then I was advised to use gets(mystr); because it can read all the stirng. But when I use gets the result is the same as the input string and nothing happens.

#include <stdio.h>
#include <stdlib.h>
#include <string.h>
#define N 100

int main(int argc, char *argv[])
{
   char mystr[N] ,result[N];
   char ch;
   int i,k;
   k=0;

   printf("enter string \n");   
   //gets(mystr);///////////////////////////
   //scanf("%s",&mystr);///////////////////
   printf("enter char \n");  
     scanf("%c",&ch);
     scanf("%c",&ch);

  for ( i = 0; i <= strlen(mystr); i++ )
  {
    if (mystr[i] != ch)
    {
      result[k]=mystr[i];
      k++;
    } 
  }
   puts(result);
   system("pause");
   return 0;
}

Answer 1

 scanf("%c",&ch);
 scanf("%c",&ch);

That second scanf is your problem. It’s picking up the new-line character that you enter after the letter you want to remove (and overwrites the previous value of ch).

Get rid of it.

Please note, as the man page says:

Never use gets(). Because it is impossible to tell without knowing the data in advance how many
characters gets() will read, and because gets() will continue to store characters past the end of
the buffer, it is extremely dangerous to use. It has been used to break computer security. Use
fgets() instead.