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Home/ Questions/Q 9145819
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Editorial Team
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Editorial Team
Asked: June 17, 20262026-06-17T10:36:31+00:00 2026-06-17T10:36:31+00:00

I have public class A { static X s_x = new X(A.class); } and

  • 0

I have

public class A {
    static X s_x = new X(A.class);
}

and

public class B {
    static X s_x = new X(B.class);
}

and so on for many classes without any special relationship or commonality. What I really wish I could do is have s_x initialized in a superclass, but with descendant-class-specific code; this is impossible since static code is not overridable. So, I want to at least make my copy-paste easier. I want a magic expression which evaluates to the Class object, i.e. to write:

    static X s_x = new X(/* magic expression here */);

where the magic expression is the same regardless of the class in which I declare my X in, but does the same as the examples above. Second-best option would be a static method to the same effect.

Notes:

  • Java 6 if possible.
  • This question is not (necessarily) about logging…
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-17T10:36:32+00:00Added an answer on June 17, 2026 at 10:36 am

    Some of the answers here have the idea for a solution, but not quite the code snippet I need. So here it is, working on any JVM:

    static X s_x = new X(getClassStatic());
    
    public static Class<?> getClassStatic() {
        try {
            // we're using the third highest stack element, since the
            // first highest is the getStackTrace() method, followed by this method itself. We
            // want the calling code's class.
            String name = Thread.currentThread().getStackTrace()[2].getClassName();
            return Class.forName(name);
        } catch (ClassNotFoundException e) {
            // shouldn't be able to get here...
            return null;
        }
    }
    

    or, for selected JVMs, as per Peter Lawrey’s suggestion:

    static X s_x = new X(getCallerClass(1));
    
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