Question

I have put my project in tomcat_home/webapps/ directory. The structure is : project_name/WEB-INF/classes. in WEB-INF i have put my web.xml descriptor. The problem is that when i try to run the application, it doesn’t find the files. The error is:

The requested resource () is not available.

My web.xml content is:

<?xml version="1.0" encoding="ISO-8859-1"?>
<web-app xmlns="http://java.sun.com/xml/ns/j2ee"

    xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance"

    xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"

    version="2.4">
<servlet>
   <servlet-name>Chapter1 Servlet</servlet-name>
   <servlet-class>Ch1Servlet</servlet-class>
</servlet>

<servlet-mapping>
   <servlet-name>Chapter1 Servlet</servlet-name>
   <servlet-url>/Serv1</servlet-url> 
</servlet-mapping>
</web-app>

I have also restarted the server, but it doesn’t want to work.
Any suggestions?

Answer 1

Does your servlet have a namespace. In the tag you need to fully qualify the Ch1Servlet class, i.e. my.code.Ch1Servlet

— Additional after reading comments —–

Ok, try this. Create a context for your webapp. Create a file named project_name.xml and put the following in it:

<Context path="/Serv1" docBase="webapps/project_name" 
         reloadable="true" debug="0" privileged="true">
</Context>

Now put the xml file in the webapps directory.

If you are deploying a WAR then replace the docBase as “webapps/project_name.war”