Question

I have question about the sql query.

I am trying to make the query that user who has all gun type times. For example.

I have table

ITEM.

|itemid |item_name|
| 1     | GunBow  |
| 2     | GunLong |
| 3     | GunShot |
|4      | SwordSm |
|5      | SwordLg |
|6      | Cannon  |

and I have table

userinventory

|used_id | name_item |
|1       | GunBow    |
|1       | GunLong   |
|1       | GunShot   |
| 2      | GunBow    |
|2       | SwardLg   |
| 2      | Cannon    |
| 3      | GunBow    |
|  3     | GunShot   |

Since user “1” has all of guns, I would like make query that returning the user 1.

What I did was…

Create Table #tmp(
Classname [varchar](50) NOT NULL
)

INSERT INTO #tmp SELECT DISTINCT iteam_name  
FROM ITEM WHERE item_name  like 'Gun%'

then…. I would like to compare to find user who has all of item..

However, I am not really sure how to do it.. because I can not use count or any aggression

Does anyway know they way to find user id who has all of Gun?

Answer 1

SELECT Q.user_id
FROM
(
  SELECT DISTINCT item_name FROM item WHERE item_name LIKE 'Gun%'
) P,

(
 SELECT DISTINCT X.name_item,Y.user_id
 FROM userinventory X, 
  (SELECT user_id,COUNT(DISTINCT name_item) as count_guns_userid
  FROM userinventory
  WHERE name_item LIKE 'Gun%'
  GROUP BY user_id
 )Y
WHERE X.user_id=Y.user_id  
) Q
WHERE P.item_name=Q.name_item
GROUP BY Q.user_id
HAVING COUNT(Q.name_item)=3;

Check the solution here on SQL Fiddle – http://sqlfiddle.com/#!3/d10b2/1