Question

I have question about try, catch and finally in Java. Consider the following scenario:

try{
//Some code here that throws IOExceotion
} 
catch (IOException ex){
System.out.println("Line 1: IOException Encountered!");
throw ex;
}
finally {
System.out.println("Line 2: I am always executed!");
}

What would be the output of the code snippet above?
Am I going to see:

Line 1: IOException Encountered!
Line 2: I am always executed!

or would it be

Line 2: I am always executed!
Line 1: IOException Encountered!

Or would it be just (since we have a throw in the catch block)

Line 1: IOException Encountered!

Basically, I haven’t found an example where there is a “throw” in the catch block and finally block following the catch block (like the example above). Can anyone shed some light on it?

Thanks.

Answer 1

You will see the first one. Finally block is executed always and as a last.