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Home/ Questions/Q 7930185
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Editorial Team
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Editorial Team
Asked: June 3, 20262026-06-03T20:20:35+00:00 2026-06-03T20:20:35+00:00

I have read a file with around 120k words so i try to do

  • 0

I have read a file with around 120k words so i try to do it fast.
have seen the:

int x = setvbuf(fp, (char *)NULL, _IOFBF, BSZ);
assert( x == 0 && fp != NULL );

option but it takes more than a second ( 1 mb file)
so now i tried this method :

fopen_s (&pFile,DICT,"rb");
if (pFile==NULL) {fputs ("File error",stderr); exit (1);}

// obtain file size:
fseek (pFile , 0 , SEEK_END);
lSize = ftell (pFile);
rewind (pFile);

// allocate memory to contain the whole file:
buffer = (char*) malloc (sizeof(char)*lSize);

// copy the file into the buffer:
result = fread (buffer,1,lSize,pFile);

how do i continue from here?
buffer holds a list of words and i want to get them one by one as fast as possible
because im building a multimap with those words.

thank you!

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-06-03T20:20:38+00:00Added an answer on June 3, 2026 at 8:20 pm

    I would read all the words like so:

    #include <vector>
    #include <string>
    #include <fstream>
    
    using namespace std;  // that's the way I like it... :-)
    
    int main()
    {
        vector<string> v;   // all the words
        string word;
        ifstream f("myfile.txt");  // open stream for input
    
        while (f) {
            f >> word;          // read word
            if (!f) break;
            v.push_back(word);  // push word into vector
        }
    
        // now v holds all the words in the file, and you can iterate them
    
        return 0;
    }
    
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