Question

I have read a thread on this but when I tried it I can`t manage to make it work.
I want to count all the male and females from a table like so:

Select 
count(case when substr(id,1, 1) in (1,2) then 1 else 0 end) as M, 
count(case when substr(id,1, 1) in (3,4) then 1 else 0 end) as F 
from users where activated=1

The ideea is that a user having an id starting with 1 or 2 is male
My table has 3 male entries and 2 are activated and it returns (the case statement doesn`t work)

M,F
2,2

Any input would be appreciated

id    activated
123   1
234   0
154   1

Answer 1

You should use SUM instead. COUNT will count all non null values.

Select 
SUM(case when substr(id,1, 1) in (1,2) then 1 else 0 end) as M, 
SUM(case when substr(id,1, 1) in (3,4) then 1 else 0 end) as F 
from users where activated=1