I have read that in 8085 the accumulator is a 8 bit register. Then how come the following instruction be true :
LDA address
where address is a “16-bit” address in L-H order
How can we insert a 16 bit address in a 8 bit register ?
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I have read that in 8085 the accumulator is a 8 bit register. Then how come the following instruction be true :
LDA address
where address is a “16-bit” address in L-H order
How can we insert a 16 bit address in a 8 bit register ?
You don’t insert a 16 bit address in a 8 bit register, but the byte contained at the memory address where the 16 bit points.
If the byte 30 is stored at @1234, LDA 1234 sets A to 30.