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Home/ Questions/Q 7560793
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T12:59:39+00:00 2026-05-30T12:59:39+00:00

I have read that the following code snippet will result in a compiler error

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I have read that the following code snippet will result in a compiler error

void tryAddingToList(List<? extends SuperType> list) {
  list.add(new SubType());
}

Now my question is:
Who exactly sets the restriction and how is the restriction set? Does the compiler specifically check for the add method call in such a method implementation?

If yes, what if I implement my own List and instead of add, introduce a new addToList method that does the same thing as add, and call that in the tryAddingToList method?

Even better, what if I implement my get method such that it also “secretly” adds something to the list (don’t ask me why anyone would do that; I’m just curious).

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  1. Editorial Team
    Editorial Team
    2026-05-30T12:59:40+00:00Added an answer on May 30, 2026 at 12:59 pm

    You should use super instead of extends here.

    void tryAddingToList(List<? super SubType> list) {
        list.add(new SubType());
    }
    

    Assume there are 3 types SuperType, SubType1, SubType2. In your original code, List<? extends SuperType> could be List<SubType2>, and you can’t add a SubType1 to List<SubType2>.

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