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Home/ Questions/Q 6749113
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T12:39:04+00:00 2026-05-26T12:39:04+00:00

I have read this implementation in C++; int ClockTimer::ClockMS() { return clock() * 1000

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I have read this implementation in C++;

int ClockTimer::ClockMS()
{
   return clock() * 1000 / CLOCKS_PER_SEC;
}

double ClockTimer::CLOCK()
{
    return ClockMS() * 0.001;
}

void ClockTimer::StartTimer()
{   
   _time_start = ClockMS(); 
} 

void ClockTimer::StopTimer(int verb)
{
   _time_stop = ClockMS();
}


float ClockTimer::GetElapsedTime()
{
    return (_time_stop - _time_start)  * 0.001f;
}

I guess that the result of GetElapsedTime() is in milliseconds, is that right? Why is that?

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  1. Editorial Team
    Editorial Team
    2026-05-26T12:39:05+00:00Added an answer on May 26, 2026 at 12:39 pm

    If ClockMS is returning milliseconds, then GetElapsedTime will return the time in seconds. For example, if the elapsed time (the difference between stop and start) was 1000 ms, then the return value would be 1000 ms * .001 second/ms = 1 second.

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