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Home/ Questions/Q 200441
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T17:06:43+00:00 2026-05-11T17:06:43+00:00

I have recently discovered that when I have pointers within a class, I need

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I have recently discovered that when I have pointers within a class, I need to specify a Copy constructor.

To learn that, I have made the following simple code. It compiles, but gives me runtime error when performing the copy constructor.

I am trying to copy just the value from the pointer of the copied object, but avoiding assigning the same address.

So, what’s wrong here?

    class TRY{
        public:
        TRY();
    ~TRY();
        TRY(TRY const &);

        int *pointer;

        void setPointer(int);
    };


    void TRY::setPointer(int a){
        *pointer = a;

        return;
    }


    TRY::TRY(){}


    TRY::~TRY(){}


    TRY::TRY(TRY const & copyTRY){
        int a = *copyTRY.pointer;
        *pointer = a;
    }



    int main(){

        TRY a;
        a.setPointer(5);

        TRY b = a;

        b.setPointer(8);

        cout << "Address of object a = " << &a << endl;
        cout << "Address of object b = " << &b << endl;

        cout << "Address of a.pointer = " << a.pointer << endl;
        cout << "Address of b.pointer = " << b.pointer << endl;

        cout << "Value in a.pointer = " << *a.pointer << endl;
        cout << "Value in b.pointer = " << *b.pointer << endl;

        return 0;
    }

I’ll be using this concept for other classes with lots of pointers in it, where I need to copy all values from on object to the other. Copying is initially necessary for this code, so I would like to keep the copying possibility (I won’t be hiding the copy constructor as private).

Besides, the real class I need to implement has like 10 pointers, and it might be changing with time. Isn’t there a somewhat smarter way to have a deep copy constructor in C++?…

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-11T17:06:43+00:00Added an answer on May 11, 2026 at 5:06 pm

    With the statement int* pointer you have just defined a pointer but has not allocated any memory. First you should make it point to a proper memory location by allocating some memory like this: int* pointer = new int. Then in the copy constructor again you have to allocate the memory for the copied object. Also, don’t forget to release the memory using delete in the destructor.

    I hope this example helps:

    class B
    {
    
    public:
        B();
        B(const B& b);
        ~B();
        void setVal(int val);
    
    private:
        int* m_p;
    };
    
    B::B() 
    {
        //Allocate the memory to hold an int
        m_p = new int;
    
        *m_p = 0;
    }
    
    B::B(const B& b)
    {
        //Allocate the memory first
        m_p = new int;
    
        //Then copy the value from the passed object
        *m_p = *b.m_p;
    }
    
    B::~B()
    {
    
        //Release the memory allocated
        delete m_p;
        m_p = NULL;
    }
    
    void B::setVal(int val)
    {
        *m_p = val;
    }
    
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