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Home/ Questions/Q 8009239
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Editorial Team
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Editorial Team
Asked: June 4, 20262026-06-04T18:23:13+00:00 2026-06-04T18:23:13+00:00

I have returned a list of href values from a HTML document. I want

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I have returned a list of href values from a HTML document. I want to go though every link within this list and test to see if they contain any of the values within my IMAGE_FORMAT tuple.

IMAGE_FORMAT = (
    '.png',
    '.jpg',
    '.jpeg',
    '.gif',
)

At present I am simply testing for '.jpg' e.g if '.jpg' in link.get('href'):

I’d like to extend this code to something along the lines of if [any value inside IMAGEFORMAT] in link.get('href'):

What would be the most efficient or cleanest way or doing so?

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  1. Editorial Team
    Editorial Team
    2026-06-04T18:23:15+00:00Added an answer on June 4, 2026 at 6:23 pm

    If you really want in, then maybe

    href = link.get('href')
    if any(end in href for end in IMAGE_FORMAT):
        # do something
        pass
    

    but if you actually want ends with, then use .endswith:

    >>> IMAGE_FORMAT = ('.png','.gif','.jpg','.jpeg')
    >>> 'fred.gif'.endswith(IMAGE_FORMAT)
    True
    

    Depends on how you want to treat ‘fred.gif.gz’, etc. Also note you might want to work with href.lower() if you don’t care about case.

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