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Home/ Questions/Q 6692797
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Editorial Team
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Editorial Team
Asked: May 26, 20262026-05-26T05:54:32+00:00 2026-05-26T05:54:32+00:00

I have searched the SO before I post this question here and hopefully this

  • 0

I have searched the SO before I post this question here and hopefully
this is not a duplicated one.

def print_me():
    a_list = range(1, 10)
    for idx, aa in enumerate(a_list):
        pass
    print(idx)

if __name__ == '__main__' : print_me()

Output is as follows:

8

I came from C++ world and could not figure out why idx is still in the scope when
the code is out side of for loop?

Thank you

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  1. Editorial Team
    Editorial Team
    2026-05-26T05:54:33+00:00Added an answer on May 26, 2026 at 5:54 am

    for loop doesn’t create any scope. This is the reason.

    In this particular code idx is a local variable of the print_me function.

    From the docs:

    The following are blocks:

    • a module
    • a function body
    • a class definition

    Update

    Generator expressions have their own scopes too.

    As of Python 3.0 list comprehensions also have their own scopes.

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