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Home/ Questions/Q 7513255
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Editorial Team
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Editorial Team
Asked: May 30, 20262026-05-30T00:07:28+00:00 2026-05-30T00:07:28+00:00

I have seen many times things like this: function customArrayIndexOf(item, array){ for (var i

  • 0

I have seen many times things like this:

function customArrayIndexOf(item, array){
    for (var i = 0, l = array.length; i < l; i++) {
        if (i in array && array[i] === item) return i;
    }
    return -1;
}

However, I am not sure why is the i in array needed.

I have three questions:

  • What it is doing?
  • Is it necessary?
  • When it will fail without it?
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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-30T00:07:29+00:00Added an answer on May 30, 2026 at 12:07 am

    Sparse arrays may cause a false positive without the check:

    var customArrayIndexOf = function(item, array){
        for (var i = 0, l = array.length; i < l; i++) {
            if (i in array && array[i] === item) return i;
        }
        return -1;
    },
    customArrayIndexOfNoCheck = function(item, array){
        for (var i = 0, l = array.length; i < l; i++) {
            if (array[i] === item) return i;
        }
        return -1;
    };
    
    var t=[]; t[1]=1;
    
    customArrayIndexOfNoCheck(undefined, t); // 0
    customArrayIndexOf(undefined, t); // -1
    

    (i and l should be local, i.e. declared with var)

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