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Home/ Questions/Q 8864759
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T16:19:44+00:00 2026-06-14T16:19:44+00:00

I have seen people do this way $(window).load(function(){ }); also $(document).ready(function() { }); but

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I have seen people do this way

$(window).load(function(){
});

also

$(document).ready(function() {
});

but some jquery still works outside these two functions, why?

Update

hmm. that means i can use $(window).load inside $(document).ready? or they should be seperated?

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  1. Editorial Team
    Editorial Team
    2026-06-14T16:19:46+00:00Added an answer on June 14, 2026 at 4:19 pm

    there are only stands for

    $(document).ready()
    

    .ready function to execute after the DOM is ready.

    $(window).load();
    

    Will execute after the page along with all its contents are done loading. This means that all images, css.

    If you are writing some JS code that does not depend on selecting DOM nodes or does not need the document to be fully loaded, you can and usually should put that code outside this block.

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