Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • SEARCH
  • Home
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 8638873
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: June 12, 20262026-06-12T10:51:05+00:00 2026-06-12T10:51:05+00:00

I have select query for the ascending order like… select DISTINCT (m.task_name) as TaskName,

  • 0

I have select query for the ascending order like…

select DISTINCT
    (m.task_name) as TaskName, 
    m.activity_name as ActivityName,
    m.actual_score,
    m.score,
    m.section_name 
from 
    users u, 
    som_scores m 
where 
    m.ref_student_id = '".$row['userid']."' and 
    m.section_name IN('jws1','jws2','jws3','jws4','sm1','srs1','Pws1','Pws2','lws1','sp1') 
ORDER BY 
    m.section_name ASC

I want to set the Section name in ascending order and also make the task name order by like Task1 Task2 and so on..

Means I want to display data like

1) sections name = jws1 and under the section like task
Task1 Task2 Task3 Task4

2) sections name = jws2 and under the section like task
Task1 Task2 Task3 Task4

And so on..

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-06-12T10:51:06+00:00Added an answer on June 12, 2026 at 10:51 am

    I found solution like this way “cast( SUBSTRING(TaskName, 5 ) AS unsigned ) ASC“

    select DISTINCT
            (m.task_name) as TaskName, 
            m.activity_name as ActivityName,
            m.actual_score,
            m.score,
            m.section_name 
        from 
            users u, 
            som_scores m 
        where 
            m.ref_student_id = '".$row['userid']."' and 
            m.section_name IN('jws1','jws2','jws3','jws4','sm1','srs1','Pws1','Pws2','lws1','sp1') 
        ORDER BY 
            m.section_name ASC,
            cast( SUBSTRING(TaskName, 5 ) AS unsigned ) ASC,
            ActivityName ASC
    
    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Related Questions

I have a SELECT query that I am expecting millions of results from. I
I have a select query in mysql . On each execution of this query
I have a select query which returns a list of data and I need
I have a select query. I want to replace that select query with another
Dear all, I have a select query that currently produces the following results: DoctorName
I have 6 columns in a table. I have a select query which selects
Have this query: SELECT HOUR( DATE ) AS hr, COUNT( * ) AS cnt
i have this query: SELECT `completed`.`ID` AS `ID`,`completed`.`level` AS `level`,`completed`.`completed_in` AS `completed_in`, COUNT(1) AS
I have this query SELECT zip, ( 3959 * acos( cos( radians(34.12520) ) *
I have a query that uses ORDER BY ASC and as such 0's come

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.