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Home/ Questions/Q 6954051
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Editorial Team
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Editorial Team
Asked: May 27, 20262026-05-27T14:33:22+00:00 2026-05-27T14:33:22+00:00

I have serializable class: [XmlRoot(ElementName = News), XmlType(News)] // I tried many attributes… public

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I have serializable class:

[XmlRoot(ElementName = "News"), XmlType("News")] // I tried many attributes...
public class News
{
    [XmlElement("Article")]
    public List<Article> Articles { get; set; }
}

And method for serialization:

public static void SerializeToXML(Object obj)
{
    XmlSerializer ser = new XmlSerializer(obj.GetType());
    ...
}

I would like to have the first XML element <News> but it is <ArrayOfArticle>.

Note, I’ve found many similar answers but it seems I have another problem…

If I use ...XmlSerializer(typeof(News)); instead of ...obj.GetType() everything is okay. But there is something wrong with obj.GetType(). It causes that (ser.mapping).ElementName is "ArrayOfArticle". What is the difference?

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1 Answer

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  1. Editorial Team
    Editorial Team
    2026-05-27T14:33:23+00:00Added an answer on May 27, 2026 at 2:33 pm

    The only way I’ve been able to find to do this in the past is to create a simple wrapper object which is decorated with the XmlRoot attribute and use it in place of your List.

    [XmlRoot("Articles")]
    public class Articles : List<Article> { }
    

    There could be a more standard way to achieve it but I know this works every time.

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