Sign Up

Sign Up to our social questions and Answers Engine to ask questions, answer people’s questions, and connect with other people.

Have an account? Sign In

Have an account? Sign In Now

Sign In

Login to our social questions & Answers Engine to ask questions answer people’s questions & connect with other people.

Sign Up Here

Forgot Password?

Don't have account, Sign Up Here

Forgot Password

Lost your password? Please enter your email address. You will receive a link and will create a new password via email.

Have an account? Sign In Now

You must login to ask a question.

Forgot Password?

Need An Account, Sign Up Here

Please briefly explain why you feel this question should be reported.

Please briefly explain why you feel this answer should be reported.

Please briefly explain why you feel this user should be reported.

Sign InSign Up

The Archive Base

The Archive Base Logo The Archive Base Logo

The Archive Base Navigation

  • Home
  • SEARCH
  • About Us
  • Blog
  • Contact Us
Search
Ask A Question

Mobile menu

Close
Ask a Question
  • Home
  • Add group
  • Groups page
  • Feed
  • User Profile
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Buy Points
  • Users
  • Help
  • Buy Theme
  • SEARCH
Home/ Questions/Q 659787
In Process

The Archive Base Latest Questions

Editorial Team
  • 0
Editorial Team
Asked: May 13, 20262026-05-13T23:05:02+00:00 2026-05-13T23:05:02+00:00

I have set up a Core Data model that includes an entity, Item with

  • 0

I have set up a Core Data model that includes an entity, Item with a 1->M relationship with the abstract entity Place, so that an item has many places. There are several entities with the parent set to Place.

I want to set up several UI elements depending on the descendent place types. I have a loop that looks something like this:

for (Place *place in item.places) {

}

… but I’m not sure how to detect what type the place is, and how to cast it to the proper type so that I can access its properties.

Thanks for any help!

  • 1 1 Answer
  • 0 Views
  • 0 Followers
  • 0
Share
  • Facebook
  • Report

Leave an answer
Cancel reply

You must login to add an answer.

Forgot Password?

Need An Account, Sign Up Here

1 Answer

  • Voted
  • Oldest
  • Recent
  • Random
  1. Editorial Team
    Editorial Team
    2026-05-13T23:05:03+00:00Added an answer on May 13, 2026 at 11:05 pm

    Not entirely sure what you are asking, but sounds like you have a collection of objects which are of subclasses of Place, and you need to detect the concrete type at runtime.

    Here’s how you do the branching and casting:

    for (id object in item.places) {
        if ([object isKindOfClass:[SomeConcretePlace class]]) {
            ((SomeConcretePlace *)object).someProperty = something;
    
        } else if ([object isKindOfClass:[AnotherConcretePlace class]]) {
            somethingElse = ((AnotherConcretePlace *)object).someProperty;
        }
    }
    

    Be sure to look at docs for isKindOfClass: and isMemberOfClass: in NSObject reference to understand the difference, you can use either depending on the circumstances.

    (You can substitute “id object” with “Place *object”, I was just using id in my code. — edit: or maybe you can’t if it’s abstract, see mzarra’s comment. “id” works fine.)

    • 0
    • Reply
    • Share
      Share
      • Share on Facebook
      • Share on Twitter
      • Share on LinkedIn
      • Share on WhatsApp
      • Report

Sidebar

Ask A Question

Stats

  • Questions 381k
  • Answers 381k
  • Best Answers 0
  • User 1
  • Popular
  • Answers
  • Editorial Team

    How to approach applying for a job at a company ...

    • 7 Answers
  • Editorial Team

    What is a programmer’s life like?

    • 5 Answers
  • Editorial Team

    How to handle personal stress caused by utterly incompetent and ...

    • 5 Answers
  • Editorial Team
    Editorial Team added an answer return theString.replace(/\ba[a-z]*n\b/ig, '') May 14, 2026 at 10:20 pm
  • Editorial Team
    Editorial Team added an answer DOM traversal and manipulation are some of the most helpful… May 14, 2026 at 10:20 pm
  • Editorial Team
    Editorial Team added an answer jQuery("h2").click(function(){ jQuery("div.level2").toggle(); }); Try using this code. The first line… May 14, 2026 at 10:20 pm

Trending Tags

analytics british company computer developers django employee employer english facebook french google interview javascript language life php programmer programs salary

Top Members

Explore

  • Home
  • Add group
  • Groups page
  • Communities
  • Questions
    • New Questions
    • Trending Questions
    • Must read Questions
    • Hot Questions
  • Polls
  • Tags
  • Badges
  • Users
  • Help
  • SEARCH

Footer

© 2021 The Archive Base. All Rights Reserved
With Love by The Archive Base

Insert/edit link

Enter the destination URL

Or link to existing content

    No search term specified. Showing recent items. Search or use up and down arrow keys to select an item.