Question

I have several dataframes in which I want to delete each row that matches a certain string. I used the following code to do it:

 df[!(regexpr("abc", df$V4) ==1),]

How can I delete the row that is following, e.g. if I delete row n as specified by the code above, how can I additionally delete row n+1?

My first try was to simply find out the indices of the desired rows, but that won’t work, as I need to delete rows in different dataframes which are of different lengths. So the indices vary.

Thanks!

Answer 1

Use which() on your logical expression and then you can just add 1 to the result.

sel <- which(grep("abc", df$V4))
sel <- c(sel, sel+1)
df[-sel,]