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Home/ Questions/Q 3313384
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Editorial Team
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Editorial Team
Asked: May 17, 20262026-05-17T22:06:33+00:00 2026-05-17T22:06:33+00:00

I have several forms on one page, they’re all the same, but have different

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I have several forms on one page, they’re all the same, but have different hidden values:

<?php foreach ($results as $result): ?>

<form method="POST" action="edit.php"> 

<input type="hidden" name="id" value="<?php echo $result['id']; ?>">

<input type="submit" name="action" value="Edit">

</form>

<?php endforeach; ?>

I want id to be submitted using $.post when this is clicked to edit.php, however if I use $(“#id”).val() (I’m trying to post the hidden input which is named id), it only selects the first id value in the page, and not the one that was clicked by the submit button.

$.post("edit.php", { id: $("#id").val(), action: "Edit" },
function(data){
alert("Data Loaded: " + data); //im using fancybox here to display an inline frame
});

How can I submit the id of the current form clicked?

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  1. Editorial Team
    Editorial Team
    2026-05-17T22:06:34+00:00Added an answer on May 17, 2026 at 10:06 pm

    I assume you’re binding to the submit event on the forms. Use serialize instead of querying for values:

    $('form').submit(function(){
    
        $.post('edit.php', $(this).serialize(), function(data) {
            alert("Data Loaded: " + data);
        });
    
        return false;
    });
    
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