Question

I have several TestCase classes in my django application. On some of them, I mock out a function which calls external resources by decorating the class with @mock.patch, which works great. One TestCase in my test suite, let’s call it B(), depends on that external resource so I don’t want it mocked out and I don’t add the decorator. It looks something like this:

@mock.patch("myapp.external_resource_function", new=mock.MagicMock)
class A(TestCase):
    # tests here

class B(TestBase):
    # tests here which depend on external_resource_function

When I test B independently, things work as expected. However, when I run both tests together, A runs first but the function is still mocked out in B. How can I unmock that call? I’ve tried reloading the module, but it didn’t help.

Answer 1

Patch has start and stop methods. Based on what I can see from the code you have provided, I would remove the decorator and use the setUp and tearDown methods found in the link in your classes.

class A(TestCase):
  def setUp(self):
    self.patcher1 = patch('myapp.external_resource_function', new=mock.MagicMock)
    self.MockClass1 = self.patcher1.start()

  def tearDown(self):
    self.patcher1.stop()

  def test_something(self):
    ...

>>> A('test_something').run()