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Asked: 2026-05-17T20:59:27+00:00

I have several web pages with different amount of tables with different amount of

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I have several web pages with different amount of tables with different amount of columns.

I was looking on the net for a jquery spinet which gets the number of columns of the table and depending on the number of columns will define the width of each column.

Ex.

  if (noOfTdOnTable == 2) {
     tdWidth = "50%";
    }
    if (noOfTdOnTable == 3) {
      td1Width = "40%";
      td2Width = "40%";
      td3Width = "20%";
    }
    if (noOfTdOnTable == 4) {
      td1Width = "35%";
      td2Width = "25%";
      td3Width = "15%";
      td4Width = "15%";
    }

Update

Using the only answer I was given I have this at the moment but only works when there is one table on the page and I could not figure out how to apply when there are two columns.

        var num = $("table > td").length;


    if (num % 4 == 0) {
        $("table  > td:eq(0)").css("width", "50%");
        $("table > td:eq(1)").css("width", "30%");
        $("table > td:eq(2)").css("width", "10%");
        $("table > td:eq(3)").css("width", "10%");
    }
    if (num % 3 == 0) {
        $("table > td:eq(0)").css("width", "50%");
        $("table > td:eq(1)").css("width", "40%");
        $("table > td:eq(2)").css("width", "10%");
    }

This is an example of the html, but the code will apply to lots of pages with different No of Tables but all tables will have either 2,3 or 4 columns.

<html>    
    <table>
           <tr>
               <td>text</td>
               <td>text</td>
               <td>text</td>
          </tr>
    </table>

    <table>
           <tr>
               <td>text</td>
               <td>text</td>
          </tr>
    </table>

    <table>
           <tr>
               <td>text</td>
               <td>text</td>
               <td>text</td>
               <td>text</td>
          </tr>
    </table>
</html>
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1 Answer

  1. Editorial Team

    To get the number of columns:

    var num = $("#table > tr > td").length;

    To specify the width:

    $("#table > tr > td").width(w + "px");

    I hope this was what you were looking for

    Edit:

    To specify the width to a specific column:

    //if you’ve specified an id to each td

    $("#td1").width(td1Width+"px");

    //if you just use classes to identify them

    $("td.td1", "#table1").width(td1Width+"px");

    I would also recommend you to look into find() and end() to select columns in an efficient way. since making a $() call is a more expensive operation:

    $("#table1").find("#td1").width(td1Width+"px").end().find("#td2")...

    Edit 2

    try this instead

    $("table > tr > td:eq(0)").css("width", "50%");

    or even better

    $("table > tr > td").eq(0).css("width", "50%").end()
                    .eq(1).css(...etc;

    “table” will select all tables on the page; use id or class to identify which table you require.

    Edit 3 (final!!)

    Ok, now i can see all the code i can give a better answer. try this:

    var num;
var $tds;
$("table").each(function(i, t) {
   $tds = $("td", t);
   num = $tds.length;

   if (num % 4 == 0) {
        $tds.eq(0).css("width", "50%").end()
            .eq(1).css("width", "30%").end()
            .eq(2).css("width", "10%").end()
            .eq(3).css("width", "10%");
    }
    if (num % 3 == 0) {
        //etc
    }
});

    I hope this is a better answer 🙂

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