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Home/ Questions/Q 8919259
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Editorial Team
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Editorial Team
Asked: June 15, 20262026-06-15T05:58:27+00:00 2026-06-15T05:58:27+00:00

I have simple function such as: void fun(vector<int> vec) { //… } void fun(int*

  • 0

I have simple function such as:

void fun(vector<int> vec)
{
//...
}

void fun(int* smth)
{
//...
}

No when i write in my program.

fun({2,3});

It calls me fun with vector argument i know it is in new C++ extended initializer lists but i would like to use new C++ and tell compiler that this is only a array of int’s how i can do it?

EDIT:

It would be nice to do it in 1 line 🙂

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  1. Editorial Team
    Editorial Team
    2026-06-15T05:58:28+00:00Added an answer on June 15, 2026 at 5:58 am

    You can’t initialise a pointer with an array, because a pointer is not an array (despite the appearance in some situations that this is occuring, it is not).

    You’ll have to pass a pointer to a pre-existing array. Alternatively, use the vector overload — surely, you prefer this one anyway?! And if the two functions do different things then why are they overloads of one another (i.e. why does it matter)?

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