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Home/ Questions/Q 8828683
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Editorial Team
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Editorial Team
Asked: June 14, 20262026-06-14T07:39:47+00:00 2026-06-14T07:39:47+00:00

I have simple hibernate mapping <class name=com.domain.OtherAccount table=ACCOUNT> <composite-id > <key-property name=acctype column=acctype type=java.lang.Character></key-property>

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I have simple hibernate mapping

      <class name="com.domain.OtherAccount" table="ACCOUNT">
          <composite-id >
            <key-property name="acctype" column="acctype" type="java.lang.Character"></key-property>
            <key-property name="accnum" column="accnum" type="java.lang.Integer"></key-property>
          </composite-id>
         <property name="accholder"></property>
      </class>

I do not want to create separate class for Composite Key. So, acctype and accnum are part of OtherAccount class only. Class implements serializable interface and hashCode() and equals() methods.

I am able to create new object and persist it using, session.save().
But how can I retrieve existing object ? In session.get() method how to specify composite key ?

  In session.get(OtherAccount.class, HOW TO SPECIFY COMPOSITE KEY HERE )
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  1. Editorial Team
    Editorial Team
    2026-06-14T07:39:48+00:00Added an answer on June 14, 2026 at 7:39 am

    Create an instance of OtherAccount and set just those two fields. Hibernate doesn’t care that the instance has more fields than it needs.

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