Question

I have slimmed my problem down to the following code:

#include <iostream>

using namespace std;

struct hello
{
    int array[4];
    array[0] = 1;
    array[1] = 2;
    array[2] = 3;
    array[3] = 4;
};

And when I compile this I still get the ‘array does not name a type’ error, on every line where I assign a value.
AFAIK this error is caused when a variable is nto declared, even though I declare array right above the assignment.

Answer 1

Assignment statements like array[0] = 0; cannot go into the struct definition, the need to go into an executable block of code like a function, a constructor or similar.

struct hello
{
    int array[4];
    hello(){
        array[0] = 1;
        array[1] = 2;
        array[2] = 3;
        array[3] = 4;
    }
};