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Home/ Questions/Q 232979
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Editorial Team
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Editorial Team
Asked: May 11, 20262026-05-11T20:03:45+00:00 2026-05-11T20:03:45+00:00

I have some action methods behind an Authorize like: [AcceptVerbs(HttpVerbs.Post), Authorize] public ActionResult Create(int

  • 0

I have some action methods behind an Authorize like:

[AcceptVerbs(HttpVerbs.Post), Authorize]
public ActionResult Create(int siteId, Comment comment) {

The problem I have is that I’m sending a request through AJAX to Comment/Create with

X-Requested-With=XMLHttpRequest

which helps identify the request as AJAX. When the user is not logged in and hits the Authorize wall it gets redirected to

/Account/LogOn?ReturnUrl=Comment%2fCreate

which breaks the AJAX workflow. I need to be redirected to

/Account/LogOn?X-Requested-With=XMLHttpRequest

Any ideas how that can be achieved? Any ways to gain more control over what happens when Authorization is requested?

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  1. Editorial Team
    Editorial Team
    2026-05-11T20:03:45+00:00Added an answer on May 11, 2026 at 8:03 pm

    Thanks to Lewis comments I was able to reach this solution (which is far from perfect, posted with my own comments, if you have the fixes feel free to edit and remove this phrase), but it works:

    public class AjaxAuthorizeAttribute : AuthorizeAttribute {
        override public void OnAuthorization(AuthorizationContext filterContext) {
            base.OnAuthorization(filterContext);
            // Only do something if we are about to give a HttpUnauthorizedResult and we are in AJAX mode.
            if (filterContext.Result is HttpUnauthorizedResult && filterContext.HttpContext.Request.IsAjaxRequest()) {
                // TODO: fix the URL building:
                // 1- Use some class to build URLs just in case LoginUrl actually has some query already.
                // 2- When leaving Result as a HttpUnauthorizedResult, ASP.Net actually does some nice automatic stuff, like adding a ReturnURL, when hardcodding the URL here, that is lost.
                String url = System.Web.Security.FormsAuthentication.LoginUrl + "?X-Requested-With=XMLHttpRequest";
                filterContext.Result = new RedirectResult(url);
            }
        }
    }
    
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